An object weighs 40N in air , weighs 20N when submerged jn water and 30N submerged in a liquid of unknown density .what is the density of the liquid?

502.51 kg/m^3

Explanation:

Upthrust on object in water is 40 - 20 = 20 N

Upthrust is equal to the buoyancy forces given as

B = pgv

p is density of water 1000 kg/m^3

g = acceleration due to gravity 9.81 m/s^2

v is the volume of liquid displaced.

Therefore

B = 1000 x 9.81 x v

20 = 9810v

v = 2.038x10^-3 m^3

For Upthrust in unknown liquid, we have 40 - 30 = 10 N

Bouyancy force for the liquid will be

B = P x 9.81 x 2.038x10^-3

NB- the same volume of fluid will be displaced i.e 2.038x10^-3 m^3

Equating we have

10 = P x 9.81 x 2.038x10^-3

10 = 0.0199p

p = 10/0.0199 = 502.51 kg/m^3

the answer is either c or d i think its d

the correct answer is "c": the pillars proclaimed his regret at the bloodshed at the battle of kalinga and his conversion to buddhism.

the kalinga war is considered as one of the largest battles in the history of india. it was fought between the between the maurya empire, which ruled the lands of what is now known as india at the time, and the independent feudal kingdom of kalinga.

the army of maurya empire, led by its king ashoka, fought a prolonged war against kalinga. the war ended around 262 bce with the victory of the maurya empire. it is believed that ashoka, after having witnessed the loss of many lives during this war, felt deep responsibility and eventually converted into buddhism.