During a medieval battle, a catapult placed on a summit throws a tarball at an angle of 27.5◦above the horizontal direction. The tarball’s speed at the top of its trajectory is 43.3 m/s. The tarball then lands at a point on the ground within enemy lines, horizontally 321 m from its launch point, striking an enemy unit. Let us neglect air resistance. (a) How high is the highest point of the tarball’s trajectory, from the launch height? (b) What is the vertical distance between the tarball's launch point and the tarball’s point of a strike at the ground?

an obstruction

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.

option number c is the right answer.