Let V(x)=−x2+2x−4 and W(x)=−x3+2x2+x+5. Find V(x)−W(x).

Step-by-step explanation:

v(x) - W(x) = x² + 2x  - 4 - [x³ + 2x² + x + 5]

                = x² + 2x - 4 - x³ - 2x² -x - 5

                = x² - 2x² - x³ + 2x - x -4 - 5

               =  -x² - x³ + x - 9

x³ - 3x² + x - 9

Step-by-step explanation:

V(x) - W(x) =

- x² + 2x - 4 - (- x³ + 2x² + x + 5) ← distribute parenthesis by - 1

= - x² + 2x - 4 + x³ - 2x² - x - 5 ← collect like terms

= x³ - 3x² + x - 9

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)

step-by-step explanation: