A and B are partner in a business .A contribution RS 20000 and B rs 30000 a however acts as a manager the understanding being that of the profit should get 25% for his service as manager the remaining divided in the ratio of their contribution .If B ges Rs 1350 Ashish share what would A get

Rs 1,650

Step-by-step explanation:

The given contribution are;

A contributes Rs 20,000, and B contributes Rs 30,000

The percentage of the profit A receives as manager = 25%

The amount of the profit divided in the ratio of their contribution = The remaining profit (75%)

The amount B gets = Rs1,350

The amount A gets = required

The ratio of their contribution at which the remaining profit is shared = 20,000:30,000 = 2:3

Where, out of 5 parts of 75% of the profits, B gets 3, while A gets 2

Let P represent the profit, we have;

B's share = 3/5× 0.75 × P = 1,350

∴ P = (5 × 1,350/3)/0.75 = 3,000

A gets 25% of the profits and 2/5 of the 75% remaining profit

∴ The amount A gets = 0.25×3000 + (2/5)×0.75×3000 = 1,650

Or simply put;

A gets the remainder of the profit which is Rs 3,000 - Rs 1,350 = Rs 1,650

the image of (6, 9) under a dilation is (4, 6). the scale factor is

d

step-by-step explanation:

hello and welcome!

so, when we see the words "proportional" along with a table, we need to know that we're looking numbers that divide by the same thing.

looking at this table, we simply have to do a trial and error, and divide to see which numbers have the same quotient. if you look at choice a & c, they both have equal quotients for three of the numbers, with one exception, so those can't be the answer. looking at b, there is no similarity, so that can't be it. then, we see d; if you divide all the numbers in the table, you'll see that they all divide by two, which is a proportional relationship, and our answer!

also, always remember that the x will always be the number that goes into y, and somewhere behind this table, is a formula. for this specific table, the formula would be:

since our x-value is being divided by two to get the y-value. and if they were to ask for more numbers in the series, this is the formula you would use to find them.