When completely filled with water, the beaker and its contents have a total mass of 326.75 g. what volume does the beaker hold? use =1.00 g/ml as the density of water.

0.003060 cm³

Explanation:

Mass of water = m = 326.75 gram

Density of water = ρ = 1.00 g/mL = 1 g/cm³

density = mass / volume

⇒volume = density / mass

⇒volume = 1 / 326.75

⇒Volume = 0.0030604 cm³

∴ Volume held by beaker = 0.0030604 cm³

Here the combined mass of the beaker and water is given so the volume found will be of the beaker as well as the liquid. But, it can be seen that the volume is so small that subtracting the beaker mass would have negligible effect.

one person pulls 90n one way and the other has 100n pulling the other way.

so the net force = 90 - 100 = -10n,

or the ans can be 10n if the picture shows -90n and 100n instead.

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .