What is the concentration of nitrate ions in a 0.125 m mg(no3)2 solution

The dissociation of Mg(NO₃)₂ can be expressed as follow,

       Mg(NO₃)₂ --> Mg²⁺ + 2NO₃⁻

Each mole of the Mg(NO₃)₂ will dissociate into 2 moles of NO₃⁻. Thus, to determine the concentration of the nitrate ions, we multiply the given value of two. 
           M = (0.125M)(2) = 0.250M

ANSWER: 0.250 M

We have that the concentration of the nitrate ions  is mathematically given as

M= 0.250M

The concentration of the nitrate ions

Question Parameters:

Generally the equation for the Reaction   is mathematically given as

Mg(NO₃)₂ --> Mg²⁺ + 2NO₃⁻

Each mole of the Mg(NO₃)₂ will dissociate into 2 moles of NO₃⁻.

the concentration of the nitrate ions is    

M = (0.125M)(2)

M= 0.250M

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Ithink it would be 160 people

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