Use quadratic regression to find a function that fits the following points. (-2,-16), (3,11), (0,2).

  y = -1.2x² +6.6x +2

Step-by-step explanation:

The quadratic regression function of a calculator or spreadsheet can do this for you. The resulting function is ...

  y = -1.2x² +6.6x +2

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If you want to do this by hand, put the given (x, y) values into the formula ...

  ax² +bx +c = y

and solve the resulting system of equations.

The third point tells you c=2, so you can simplify the system of equations to ...

  a(-2)² +b(-2) +2 = -16   ⇒   4a -2b = -18   ⇒   2a -b = -9

  a(3)² +b(3) +2 = 11   ⇒   9a +3b = 9   ⇒   3a +b = 3

Adding these equations together gives ...

  (2a -b) +(3a +b) = (-9) +(3)

  5a = -6 . . . . . . . . simplify

  a = -1.2 . . . . . . . divide by 5

  b = 3 -3a = 3 -3(-1.2) = 6.6 . . . . from the second equation

Now we know the coefficients are a=-1.2, b=6.6, c=2, so the function is ...

  y = -1.2x² +6.6x +2

tube or goog would be a great resource to with that question

step-by-step explanation:

let

we know that

the y-intercept is the y-coordinate of the point when the value of x is equal to zero

so

the y-coordinate of the point a is the y-intercept

the answer part a) is

the value of y-intercept is

part b) find the slope m

we know that

the value of the slope is equal to

substitute the values

therefore

the answer part b) is

the value of the slope is equal to

the general answer is

the slope is

the value of y-intercept is