Question 1: Write the specific equation for the kinetic energy E (measured
in Joules) of an 1100-kg car. Use this equation to compare the kinetic
energy of an 1100-kg car moving at a velocity of 10 meters per second to
the kinetic energy of the same car moving at 3 times the velocity.

Step-by-step explanation:

KE = ½mv²

KE₁₀ = ½(1100)10² = 55000 = 55 kJ

KE₃₀ = ½(1100)30² = 495000 = 495 kJ

9 times greater

i = 2 / - 5

step-by-step explanation:

evaluation of ( 2 - 4 ) ( p + q ) when p = 2 and q = 5 i, by putting values of p and q,                                                                    

don't know what that says sorry i can't you

step-by-step explanation:

idk what it says