3x + 12 - 6x ≤ -9 help please

7

Step-by-step explanation:

simple it's the inequalities version of multi-steps so first subtract 12 from both sides so...

3x-6x < -21

then combine like terms

-3x < -21

then divide by negative three

x < 7

x≥7

Step-by-step explanation:

Let's solve your inequality step-by-step.

3x+12−6x≤−9

Step 1: Simplify both sides of the inequality.

−3x+12≤−9

Step 2: Subtract 12 from both sides.

−3x+12−12≤−9−12

−3x≤−21

Step 3: Divide both sides by -3.

−3x  over −3  ≤  −21  over −3 =  

x≥7

hope this helps

sorry if wrong

#Virgo2007

is it 35

step-by-step explanation:

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.