On a baseball field, the pitcher’s mound is 60.5 feet from home plate. during practice, a batter hits a ball 257 feet at an angle of 31° to the right of the pitcher’s mound. an outfielder catches the ball and throws it to the pitcher. approximately how far does the outfielder throw the ball?

207.49 ft.

Step-by-step explanation:

Please find the attachment.

We have been given that on a baseball field, the pitcher’s mound is 60.5 feet from home plate. During practice, a batter hits a ball 257 feet at an angle of 31° to the right of the pitcher’s mound.

We can see from our attachment that point home plate, pitcher's mound and outfielder form a triangle and we need to figure out distance between pitcher's mound and outfielder (c).  

As we have been given two sides and included angle of our triangle, so we will use law of cosines to solve our given problem.

Upon substituting our given values in above formula we will get,

Let us take square root of both sides of our equation.

Therefore, the outfielder thrown the ball approximately 207.49 ft.

a.

step-by-step explanation:

step 1 distribute 2 to every term in the parentheses

step 2 add 10 on both sides of the equal sign

so the possibilities of the measurement of the side of the triangle are either it is longest side or not the longest side

when it is the longest side

s < 25 + 35s < 60

if it is not the longest side

35 < 25 + s10 < sso 10 < s < 60so the perimeter70 < p < 130