Abaseball is thrown upwards from a height of 5 feet with an initial speed of 64 feet per second, and its height h (in feet) from the ground is given by h(t) = 5 + 64t – 16t2 where t is time in seconds. using a graphing calculator, determine at what time the ball reaches its maximum height

It will take 2 seconds to reach its maximum height.          

Step-by-step explanation:

We have given, A baseball is thrown upwards from a height of 5 feet with an initial speed of 64 feet per second, and its height h (in feet) from the ground is given by where t is time in seconds.

We have to find, Using a graphing calculator, determine at what time the ball reaches its maximum height.

Solution:

The equation represented as

Where, t is time in seconds and h is the height.

Now, We plot the graph of the given equation.

Refer the attached graph below.

The given equation is a downward parabola with y coordinate of vertex of the parabola will give its maximum height and x coordinate will given the time at which the ball is at maximum height

The vertex of the equation is given by V=(2,69)

Maximum height = 69 feet

Time to reach maximum height = 2 seconds

Therefore, It will take 2 seconds to reach its maximum height.

step-by-step explanation:

a rhombus is a parallelogram enjoying his symmetry.

the answer is a i belaeve atleast thats what my calculator just gfave me

step-by-step explanation: