A banner in the shape of an isosceles triangle is hung over the side of a building. The banner has a base of 30ft (at the roof), a height of 20ft, and weighs 50lb. Write down an integral for the work required to lift the banner entirely onto the roof of the building.

W = 9600000 joules

Step-by-step explanation:

From the given information:

The area of the banner = 1/2 × 30 × 20 = 300 ft²

The mass of the banner = 300 × 50 = 15000 pounds

Now; the integral for the required work is:

here;

h = height of the building

F = mg = 15000g

g = 32 ft/s²

Therefore;

W = 9600000 joules

the answer is:

the answer is:

to solve the problem, we need to remember the quotient of power property, it's defined by the following relation:

if we have a quotienf of powers that have the same base, we need to keep the same base and subtract the exponent of the denominator power to the exponent of the numerator power.

so, we are given the expression:

then, calculating we have:

hence, the answer is:

have a nice day!

the height of the surface increases from the center out to the sides of the road.

step-by-step explanation:

as we move out we move away from the x-axis.

and as mentioned in the problem statement that height of a road increases when we move away from the center x.

hence proved that 3rd option

the height of the surface increases from the center out to the sides of the road.

is the correct option.