A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using the equation, find out the time at which the rocket will reach its max, to the nearest 100th of a second y=-16x^2+235x+133

Step-by-step explanation:

Given tq equation of the height reached by the rocket as y=-16x^2+235x+133

The velocity of the object at its maximum height is zero

v = dy/dx = 0(at max height)

v =-32x +235

0 =-32x+235

x = 235/32

x = 7.34

Hence the rocket will reach its maximum height after 7.34seconds

the bottom of the spinner is not flat.

step-by-step explanation:

step-by-step explanation:

12: 00 p.m. to 7: 00 p.m. is a total of 7 hours.

4: 00 p.m. to 7: 00 p.m. is a total of 3 hours.

this means that from 4: 00 p.m to 7: 00 p.m. this represents 3/7 of what was lost from 12: 00 p.m. to 7: 00 p.m.

after knowing this, after doing 11,600 - 6,800 = 4,800

4,800 represents 3/7 of what was lost for 7 hours.

we then divide 4,800 by 3 which gets 1,600.

because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200.   after adding 11,200 to how much water was left at 7: 00 p.m. which was 6,800. 11,200 + 6,800 = 18,000

this means that the pool originally had 18,000 gallons in the pool.

you can also check your work by doing 18,000 - 4(1600), which becomes           1800 - 6400 which gets you 11,600.