Question 1.) 3(2x + 4) = 2(2x - 2) Question 2.) 4.3x - 6 = 8 + 2.3x

Question 3.) 6(x-8) = 8x -36

Question 4.) -1 + 3 (x + 2) = ( 1 + 8x)

Please show work if you can

#1. How to solve your question

Your question is

3(2+4)=2(2−2)

3(2x+4)=2(2x-2)3(2x+4)=2(2x−2)

Solve

1

Distribute

3(2+4)=2(2−2)

{\color{#c92786}{3(2x+4)}}=2(2x-2)3(2x+4)=2(2x−2)

6+12=2(2−2)

{\color{#c92786}{6x+12}}=2(2x-2)6x+12=2(2x−2)

2

Distribute

again

6+12=2(2−2)

6x+12={\color{#c92786}{2(2x-2)}}6x+12=2(2x−2)

6+12=4−4

6x+12={\color{#c92786}{4x-4}}6x+12=4x−4

3

Subtract 

12

1212

 from both sides of the equation

6+12=4−4

6x+12=4x-46x+12=4x−4

6+12−12=4−4−12

6x+12{\color{#c92786}{-12}}=4x-4{\color{#c92786}{-12}}6x+12−12=4x−4−12

4

Simplify

Subtract the numbers

Subtract the numbers

again

6=4−16

6x=4x-166x=4x−16

5

Subtract 

4

4x4x

 from both sides of the equation

6=4−16

6x=4x-166x=4x−16

6−4=4−16−4

6x{\color{#c92786}{-4x}}=4x-16{\color{#c92786}{-4x}}6x−4x=4x−16−4x

6

Simplify

Combine like terms

Combine like terms

again

2=−16

2x=-162x=−16

7

Divide both sides of the equation by the same term

2=−16

2x=-162x=−16

22=−162

\frac{2x}{{\color{#c92786}{2}}}=\frac{-16}{{\color{#c92786}{2}}}22x=2−16

8

Simplify

Cancel terms that are in both the numerator and denominator

8

step-by-step explanation:

to find the amount of gift bags to use all the supplies, find the gcf or greatest common factor. this is the largest number which multiplies evenly into each term.

48 has factors: 1, 2, 3, 4, 6, 8, 12. 16, 24, 48

80 has factors: 1, 2, 4, 5, 8, 10, 16, 20, 40, 80

64 has factors: 1, 2, 4, 8, 8, 16, 32, 64

the highest number factor they all share in common is 8. this means there will be 8 bags with 6 pencils, 10 markers, and 8 stickers in each bag.