1. the base of a solid is a quadrant of a circle of radius a. each cross section perpendicular to one edge of the base is a semicircle whose diameter lies in the base. find the volume.

2. find the volume of the solid of revolution generated when the area bounded by the curve y = x, y=0, and x=4 is revolved around i) the x-axis and ii) the y-axis.

3. a hole of radius sqrt(3) is bored through the center of a sphere of radius 2. find the volume removed.

4. find the volume of the solid generated by revolving the region enclosed by the graphs of y =e^(−x^2), y =0 , x =0 , and x =1 about the y-axis.

5. find the length of the curve given by y = (1/3)x^3 + 1/(4x), from x=1 to x=3.

7

step-by-step explanation:

the answer would be 7

the correct answer is a.) bc< mn 5 stars if this you : )

step-by-step explanation:

if gloria has "carry over" minutes, (that is, any minutes paid for but not used in a month can be applied to her payment for minutes in the next month,) her total usage for the three months is: total minutes = 320 + 243 + 489 = 1052 minutes number of 200 minute blocks = 1052/200 = 5 r52 (that is 5 with a remainder of 52) rounding up the number of 200 minute blocks gives her usage for the three months as 6 blocks. the cost for six blocks is 6 x $25 = $150 she also has 200 - 52 or 148 carry over minutes if gloria pays each month and unused minutes are lost, applying the rounding up procedure to each month gives: first month usage of 320 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 second month usage of 243 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 third month usage of 489 minutes rounds up to 3 blocks of 200 minutes for a payment of 3 x $25 = $75 total payments for the three months are $50 + $50 + $75 = $175 get the plan with carry over minutes!

i agree because i see the other persons thinking is clear