Suppose that salaries for recent graduates of one university have a mean of $24,800 with a standard deviation of $1100. Using Chebyshev's Theorem, what is the minimum percentage of recent graduates who have salaries between $21,500 and $28,100

The mininum percentage of recent graduates is 88.9%

Step-by-step explanation:

We are given:

Mean value = $24,800

Standard deviation = $1100

Minimum value of salary = %21,500

Maximum value of salary = %28,100

The equation for Chebyshev's Theorem is given by:

          .....(1)

To calculate the value of 'k', we first subtract the mean value from the maximum value.

⇒ [28,100 - 24,800] = 3300

Secondly, dividing the above-calculated value by the standard deviation, we get:

Putting value of 'k' in equation 1, we get:

Hence, the mininum percentage of recent graduates is 88.9%

just do 5.2 + 2 ( 7.2) and 1/3 x 3 (.9) and youv'e got your equation. 0.9( 9/10) + 7.2 ^2 = 16.4 hope i could !

step-by-step explanation: