Suppose that surface σσ is parameterized by r(u, v)=⟨ucos(6v),usin(6v),v⟩r(u, v)=⟨ucos(6v),usin(6v),v⟩, 0≤u≤70≤u≤7 and 0≤v≤1π30≤v≤1π3 and f(x, y,z)=x2+y2+z2f(x, y,z)=x2+y2+z2. set up the surface integral (you don't need to evaluate it). ∫σ∫f(x, y,z)ds=∫r∫f(x(u, v),y(u, v),z(u, v))∥∥∥∂r∂u×∂r∂v∥∥∥da∫σ∫f(x, y,z)ds=∫r∫f(x(u, v),y(u, v),z(u, v))‖∂r∂u×∂r∂v‖da

cheater

step-by-step explanation:

x coordinate can be written by using the formula, x= x1 + 2/5(x2 - x1)

step-by-step explanation:

formula

x = x1 + p/w(x2 - x1)

let the line segment ab with a(x1,y1) and b(x2,y2)

a point(x,y) divide ab in the ratio, 2: 3 the x coordinate can be written as

x = x1 + p/w(x2 - x1)

here p=2 and w = 2+3

therefore,

x coordinate can be written by using the formula, x= x1 + 2/5(x2 - x1)

similarly y coordinate y = y1 + 2/5(y2 - y1)