Let f(x, y)=x2ex2 and let r be the triangle bounded by the lines x=2, x=y/2, and y=x in the xy-plane. (a) express ∫rfda as a double integral in two different ways by filling in the values for the integrals below. (for one of these it will be necessary to write the double integral as a sum of two integrals, as indicated; for the other, it can be written as a single integral.)

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step-by-step explanation:

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

answer: 1 + 1 = 11

step-by-step explanation:

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