It is claimed that the expected length of time some computer part may work before requiring a reboot is 26 days. in order to examine this claim 80 identical parts are set to work. assume that the distribution of the length of time the part can work (in days) is exponential. the central region that contains 70% of the distribution of the average is of the form e(x) ± c, where e(x) is the expectation of the sample average. the value of c is (you are asked to apply the normal approximation to the distribution of the average of the 80 parts that are examined. the answer may be rounded up to 3 decimal places of the actual value.)

mia khalifa

step-by-step explanation:

1. sometimes

2.   never

3   .08c = 7.50+.05c   250 pages

step-by-step explanation:

1.   sometimes

the theoretical probability of rolling a 1 is 1/6.   perhaps you got really lucky and never rolled a 1   in those 60 times.   your experimental probability is 0.   or perhaps you rolled a 1   20 times.   your experimental probability is 20/60 is 1/3.     it really just depends on how you rolled in that experiment.

2.   never

the probability of the event occurring is 1.   that is being 100 % sure it will happen.   that is the maximum amount of confidence we have.

3.   no customer card cost:   .08 times number of pages

customer card cost:   7.50 + .05 times number of pages

we want to find when it costs the same amount, so we will set these equal

let c = number of pages

.08c = 7.50+.05c

subtract .05c from each side

.08c-.05c = 7.5+.05c-.05c

.03c=7.5

divide each side by .03

.03c/.03 = 7.5/03

c =250  

the cost is the same at 250 pages

what’s the question?