Customers of the key refining company charge an average of $70 per month. the distribution of amounts charged is approximately normal, with a standard deviation of $10. what is the probability of selecting a credit card customer at random and finding the customer charged between $70 and $83

0.4032 is the probability of selecting a credit card customer at random and finding the customer charged between $70 and $83.      

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = $70

Standard Deviation, σ = $10

We are given that the distribution of amounts charged is a bell shaped distribution that is a normal distribution.

Formula:

P(customer charged between $70 and $83)

Thus, 0.4032 is the probability of selecting a credit card customer at random and finding the customer charged between $70 and $83.

you could deduce the conclusion directly using the facts pertaining to the specific situation.

hope this .