Write the equation of the line that passes through -5,1 and 2,1 in the form y=mx+b

First, let's find the slope of the line segment that passes through the given poins (-5,1) and (2,1).  (Note:  Please use parentheses here.

           1-1

m = = 0.  The slope of this segment is zero; the segment is horiz.

           2-(-5)

The desired line is therefore horiz.  It passes thru (-5,1) and (2,1).  Note that the y-coordinates are both 1.  Thus, the equation of this horiz. line is y = 1.

stops on an even number.

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)