Astandby generator powered by and internal combustion engine has a rated capacity of 100kw. assuming that the generator is 90% efficient how much horsepower must the engine deliver to the generator at full load? assuming that the thermal efficiency of the engine is 35% how much diesel fuel will the engine consume in one hour at full load?

a)148.9hp

b)25.2kg

Explanation:

Hello!

To solve this exercise follow the steps below.

1. Find the power the generator needs to operate at 100Kw,

This is done by remembering that efficiency in a generator is the ratio between real power and ideal power.

where

α=generator efficiency =0.9

Wi=nominial or ideal efficiency=100Kw

Wr=real effiency

solving for Wr

the power that the combustion engine must deliver is 111Kw for the generator to deliver 100Kw, Now use conversion factor to know the value in horsepower

2. Find the engine supply power using the combustion engine efficiency definition

α=engine efficiency =0.35

Wo = output power

=111.11Kw

Wi = supply power

solving for Wi

3. use the calorific power of diessel (CP=45KJ /g) to find the mass flow, remember that the supply power is the product of the mass flow and the caloric power

Wi=m(CP)

m=mass flow

solving for m

4. The mass flow is the ratio between the mass consumed and the time (1h) in this way we can find the diessel consumed in one hour at full load

M=diessel mass consumed

m=M/t

M=mt

yes indeed

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explanation:

which ordered pair is not in the solution

y > -1/2x + 5

y ≤ 3x - 2

a) (5,3) b) (4,3)

c) (3,4) d) (4,4)