A chemist prepares a solution of calcium sulfate CaSO4 by measuring out 0.03g of calcium sulfate into a 150.mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in /molL of the chemist's calcium sulfate solution. Be sure your answer has the correct number of significant digits.

0.00147 Molar is the molarity of the solution.

Explanation:

Molarity of the solution is the moles of compound in 1 Liter solutions.

Mass of calcium sulfate = 0.03 g

Molar mass of calcium sulfate = 136 g/mol

Volume of the calcium sulfate = 150. mL = 0.150 L ( 1 L = 0.001 mL)

0.00147 Molar is the molarity of the solution.

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml