What is the molarity of a solution made from dissolving 3.0 moles of NaCl in 250 mL of solution? 3.0 M NaCl

0.012 M NaCl

750 M NaCl

12 M NaCl

Molarity = 12 M

Explanation:

Given data:

Molarity of solution = ?

Number of moles of NaCl = 3.0 mol

Volume of solution = 250 mL (250/1000 = 0.25 L)

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

Molarity = 3.0 mol / 0.25 L

Molarity = 12 M

Explanation:

Molarity, which tells us the concentration of a solution, is found by dividing the moles of solute by the liters of solution.

1. Define Values

There are 3.0 Moles of NaCl. This is the moles of solute.

There are 250 milliliters of solution, but we need the liters.

    a. Convert mL to L

1 milliliter is equal to 0.001 liters. We can multiply the given number of              milliliters (250) by 0.001.

250 mL * 0.001 L/mL= 0.25 L

2. Calculate Molarity

Substitute the values into the formula.

Divide.

3. Define Units

1 mole per liter is equal to 1 molar.

Our answer of 12 mol NaCl/ L is equal to 12 M NaCl

The molarity is 12 M NaCl

c. because step up transformer steps up the input voltage i.e increases the input voltage  

the number of turns are greater on the secondary side of step up transformer  

transformer does not handle dc current

when [oh-] is 10-5  m, and [h3o+] is 10-9  m, the poh is 5 and ph is 9. again in both cases the sum of ph and poh is 14. however, the hydrogen ion concentration is not always going to be equal to exactly 1 x 10 raised to a negative number. for example, we skipped over the value of 2.0 x 10-7.