Aball is thrown from the height of 35 meters with an initial downward velocity of 5m/s. the ball's height h (in meters) after t seconds is given below: h=35-5t-5t^2 how long after the ball is thrown it hits the ground? round to the nearest hundredth place.

You find this value by factoring.  Factoring finds the zeros of the function.  When the ball hits the ground, it has 0 height.  Therefore, when the function goes through the x axis, it has a y value of 0.  That means that when y = 0, the ball has hit the ground.  Use the quadratic formula to factor .  Notice I rearranged the terms.  When you factor that you get zeros of -3.19 and 2.19.  The two things in math that will never EVER be negative are time and distance/length.  Therefore, that tells us that the ball hits the ground 2.19 seconds after it was thrown.

False because how does that work?