Help pls with chemistry question

1×10⁸ Hz.

Explanation:

From the question given above, the following data were obtained:

Wavelength (λ) = 3 m

Frequency (f) =?

The wavelength of a wave and it's frequency are related by the following equation:

Velocity (v) = wavelength (λ) × frequency (f)

v = λf

With the above equation, we can obtain the frequency of the light wave as follow:

Wavelength (λ) = 3 m

Velocity (v) of light = 3×10⁸ m/s

Frequency (f) =?

v = λf

3×10⁸ = 3 × f

Divide both side by 3

f = 3×10⁸ / 3

f = 1×10⁸ Hz

Therefore, the frequency of the light wave is 1×10⁸ Hz

answer

the ions in solute supperate from eachouthere