Two particles, with identical positive charges and separation of 2.55 10-2 m, are released from rest. Immediately after the release, particle 1 has an acceleration vector a1 whose magnitude is 4.65 103 m/s2, while particle 2 has an acceleration vector a2 whose magnitude is 8.55 103 m/s2. Particle 1 has a mass of 6.05 10-6 kg.
a. Find the charge on each particle. q1 = C q2 = C
b. Find the mass of particle 2. kg

Answer with Explanation:

We are given that

Distance between two charges,d=

Mass of particle 1=

a.We have to find the change on each particle .

Let

Force ,

Where

Using the formula

For particle 1

Using the value of F

b.

Using the formula

answer: the exterior temperature of commercial jet planes as they leave the stratosphere and return to the ground increases steadily.

explanation:

the lower most layer of atmosphere is troposphere which extends from 0 to 12 km above the surface of the earth. the temperature initially decreases as distance is increased from the earth's surface. commercial jets fly in lower part of the stratosphere. the stratosphere extends upto 50 km. the temperature in stratosphere starts rising again due to presence of ozone which traps the uv rays.

thus, when the planes leave the stratosphere and return to the ground, the exterior temperature increases steadily.

change tension