Copper was one of the earliest metals used by humans, because it can be prepared from a wide variety of copper minerals, such as cuprite (Cu2O), chalcocite (Cu2S), and malachite [Cu2CO3(OH)2]. Balance the following reactions for converting these minerals into copper metal. Place a coefficient in each gray box. (a) Cu2O(s) + C(s) rightarrow Cu(s) + CO2(g)
(b) Cu2O(s) + Cu2 S(s) rightarrow Cu(s) + SO2(g)
(c) Cu2 CO3 (OH)2(s) rightarrow CuO(s) + CO2(g) + H2O(g)
Use the left and rightarrow keys to move the cursor out of a superscript or subscript in the module.

a. 2 Cu₂O(s) + C(s) → 4Cu(s) + CO₂(g)

b. 2Cu₂O(s) + Cu₂S(s) → 6Cu(s) + SO₂(g)

c. Cu₂CO₃(OH)₂(s) → 2 CuO(s) + CO₂(g) + H₂O(g)

Explanation:

A reaction is balanced when you have the same amount of atoms in reactants and products.

In the reactions:

(a) Cu₂O(s) + C(s) → Cu(s) + CO₂(g)

As a general rule, you first balance oxygen and hydrogen. In products you have 2 oxygens, then:

2 Cu₂O(s) + C(s) → Cu(s) + CO₂(g)

Carbon is balanced yet. Thus, you need just to balance Cu:

2 Cu₂O(s) + C(s) → 4Cu(s) + CO₂(g)

(b) Cu₂O(s) + Cu₂S(s) → Cu(s) + SO₂(g)

Balancing oxygen:

2Cu₂O(s) + Cu₂S(s) → Cu(s) + SO₂(g)

Sulfur is balanced yet. Now you just need to balance Cu:

2Cu₂O(s) + Cu₂S(s) → 6Cu(s) + SO₂(g)

(c) Cu₂CO₃(OH)₂(s) → CuO(s) + CO₂(g) + H₂O(g)

This reaction is different because the reactant is a chemical with a lot of atoms. we will first balance Cu:

Cu₂CO₃(OH)₂(s) → 2 CuO(s) + CO₂(g) + H₂O(g)

Balancing copper, oxygen, hydrogen and carbon are balanced:

Cu₂CO₃(OH)₂(s) → 2 CuO(s) + CO₂(g) + H₂O(g)

there all right good

explanation:

the positions which points up in upward carbon and down in downward carbon are axial

and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be