+ For the reaction Pb(NO3)2 + 2KI Pbl2 + 2KNO3, how many moles of lead iodide are
produced from 237.1 g of potassium iodide?
Select one:
O a. 0.714
Ob. 5.47e4
O c. 1.54
Od 1.54

0.714 moles of will be produced from 237.1 g of potassium iodide

Explanation:

To calculate the moles :

The balanced chemical reaction is:

According to stoichiometry :

2 moles of produce =  1 mole of

Thus moles of will require=  of

Thus 0.714 moles of will be produced from 237.1 g of potassium iodide