How many mL of water would be displaced by 408 g of lead?

36 mL of water can be displace by the 408 g lead

Explanation:

Given data:

Mass of lead = 408 g

Volume of water displaced by lead = ?

Solution:

The volume of water displace by the lead would be equal to the given volume of lead.

So we will calculate the volume from given mass of lead from density formula.

Density:

Density is equal to the mass of substance divided by its volume.

Units:

SI unit of density is Kg/m3.

Other units are given below,

g/cm3, g/mL , kg/L

Formula:

D=m/v

D= density

m=mass

V=volume

Density of lead is 11.36 g/cm³.

d = m/v

11.36 g/cm³ = 408 g/ v

v = 408 g/ 11.36 g/cm³

v =36 cm³

1 cm³  = 1 mL

volume = 36 mL

36 mL of water can be displace by the 408 g lead.

i believe the answer is three water molecules