What is the mole fraction of glucose when 46.2 g glucose C 6H 12O 6 (molar mass 180.2 g/mol) is dissolved in 65.1 g water?

The mol fration of glucose is 0.0662

Explanation:

Step 1: Data given

Mass glucose = 46.2 grams

Molar mass glucose = 180.2 g/mol

Mass water = 65.1 grams

Molar mass water = 18.02 g/mol

Step 2: Calculate moles glucose

Moles glucose = mass glucose / molar mass glucose

Moles 46.2 grams / 180.2 g/mol

Moles glucose = 0.256 moles

Step 3: Calculate moles H2O

Moles H2O = 65.1 grams / 18.02 g/mol

Moles H2O = 3.61 moles

Step 4: Calculate mol fraction glucose

Mol fraction glucose = 0.256 moles / (0.256+3.61) moles

Mol fraction glucose =0.0662

The mol fration of glucose is 0.0662

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mass = 6.75 g

volume =   9 cm³

therefore:

d = mass / volume

d   = 6.75 / 9

d = 0.7 g/cm³

answer b