Consider the following reaction. so2cl2 → so2 + cl2. after collecting experimental data you found that plotting ln[so2cl2] vs. time (s) fit a straight line with the following formula. y = -0.000290t-2.30 using this information, what is the concentration of so2cl2 at 600 s?

Explanation:

Some theoretical knowledge is required here. We should understand that whenever we plot the natural logarithm, ln, of a concentration vs. time and obtain a straight line, this indicates a first-order reaction. That said, since this is the case here, we have a first-order reaction with respect to .

The linear equation has the following terms:

It is a linear form of the integrated first-order law equation:

Therefore, the rate constant, k, is:

The natural logarithm of initial molarity is:

Using the equation, we may substitute for t = 600 s and obtain the natural logarithm of the concentration at that time:

Take the antilog of both sides to find the actual molarity:

not clear