Consider this question: what is the molarity of kmno4 in a solution of 0.0908 g of kmno4 in 0.500 l of solution?
(a) outline the steps necessary to answer the question
(b) answer the question

0.0011 M.

Explanation:

Molarity of a substance , is the number of moles present in a liter of solution .

M = n / V

M = molarity

V = volume of solution in liter ,

n = moles of solute ,

Moles is denoted by given mass divided by the molecular mass ,

Hence ,

n = w / m

n = moles ,

w = given mass ,

m = molecular mass .

From the question ,

w = given mass of KMnO₄ = 0.0908 g

and ,

V = 0.500 L

Since ,

we know ,

m = Molecular mass of   KMnO₄ =  158 g/mol

using , the above formula to calculate the moles ,

n = w / m = 0.0908 g / 158 g/mol = 0.00057 mol

now , calculating the molarity as ,

M = n / V =  0.00057 mol / 0.500 L = 0.0011 M.

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