The density of a 3.37m mgcl2 (fw = 95.21) is 1.25 g/ml. calulate the molality, mass/mass percent, and mass/volume percent. so far this is what i have, but i cannot get the correct values for the mass of the solution to even begin to figure out the volume.

Answer : The molality, mass/mass percent, and mass/volume percent are, 0.0381 mole/Kg, 25.67 % and 32.086 % respectively.

Solution : Given,

Density of solution = 1.25 g/ml

Molar mass of (solute) = 95.21 g/mole

3.37 M magnesium chloride means that 3.37 gram of magnesium chloride is present in 1 liter of solution.

The volume of solution = 1 L = 1000 ml

Mass of (solute) = 3.37 g

First we have to calculate the mass of solute.

Now we have to calculate the mass of solution.

Mass of solvent = Mass of solution - Mass of solute = 1250 - 320.86 = 929.14 g

Now we have to calculate the molality of the solution.

The molality of the solution is, 0.0381 mole/Kg.

Now we have to calculate the mass/mass percent.

The mass/mass percent is, 25.67 %

Now we have to calculate the mass/volume percent.

The mass/volume percent is, 32.086 %

Therefore, the molality, mass/mass percent, and mass/volume percent are, 0.0381 mole/Kg, 25.67 % and 32.086 % respectively.

it is the most commonly accepted one