Asample containing only carbon, hydrogen, and silicon is subjected to elemental analysis. after complete combustion, a 0.7020 g sample of the compound yields 1.4 g of co2, 0.86 g of h2o, and 0.478 g of sio2. what is the empirical formula of the compound?

The empirical formula of compound is .

Explanation:

Mass of Sample= 0.702 g

Mass of = 1.4 g

Mass of = 0.86 g

Mass of = 0.478 g  

First we have to calculate moles of, and formed.

1. Moles of

Now , Moles of carbon == Moles of = 0.032

2.  Moles of =0.048mol

Now , Moles of hydrogen = Moles of =

3.  Moles of mol

Now , Moles of silicon = Moles of = 0.008 moles

Therefore, the ratio of number of moles of C : H : Si is  = 0.032 : 0.096 : 0.008

For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C=

For H =

For Si=

Thus, C: H: Si = 4 : 12 : 1

The simplest ratio represent empirical formula.

Hence, the empirical formula of compound is .

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied