Asled that has a mass of 8 kg is pulled at a 50 degree angle with a force of 20 n. the force of friction acting on the sled is 2.4 n. the free-body diagram shows the forces acting on the sled. what is the acceleration of the sled and the normal force acting on it, to the nearest tenth? 1) a = 1.3 m/s2; fn = 63.1 n 2) a = 1.6 m/s2; fn = 65.6 n 3) a = 1.9 m/s2; fn = 93.7 n 4) a = 2.2 m/s2; fn = 78.4 n

As per the question the mass of sled[m] is given as 8 kg.

The fictional force is given as 2.4 N

A force of 20 N  was exerted on the sled at angle of

Resolving the force into horizontal and vertical components we get -

and

Here is the horizontal component and is the vertical component.

Similarly

From the free body diagram we get that sum of vertical components is zero as there is no motion in vertical direction.

Hence where g is the acceleration due to gravity .

⇒

 ⇒  [here value of g is 9.8 m/s^2]

                      =63.1 N

The net motion of the body is along the  forward  direction.

            Hence   where a is the acceleration of the body.

              ⇒

Hence the option A is the right answer.

answer: the metamorphic rocks are formed when they are exposed to high pressure and high temperatures. this happens when one of the earth's plates comes in contact with the other plate by traveling in opposite directions, straight into each other or slipping under one another. the friction that is caused by this activity results in   melting of rocks and when it cools they are known as metamorphic rocks. this process needs a controlled amount of pressure and temperature otherwise it may turn into magma.