Physics, 05.02.2022 14:00 yejinschoi6362

How does Kinetic Energy and the Law of Conservation of Momentum apply to inelastic
collisions?

Answers: 1

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Answers

Answer from: skyhighozzie

Explanation:

An inelastic collision is one in which the internal kinetic energy changes (it is not conserved) . The two objects come to rest after sticking together, conserving momentum. But the internal kinetic energy is zero after the collision.

Answer from: jay8682

Explanation:

Why does the inelastic collision momentum remain conserved while the kinetic energy changes?

Imagine two objects colliding, M1 and M2. Let’s say that M1 slows down and M2 speeds up. The change in momentum for M1 will be equal to the Impulse acting on M1 which is defined as the force on M1 multiplied by the time interval the force acts. The change in momentum for M2 will be the force on M2 multiplied by that SAME time interval. The two forces are an action-reaction pair; M2 pushing on M1 and M1 pushing back on M2.

Since the two forces are equal and opposite and the time intervals are equal, the two Impulses must also be equal and opposite, and so will cancel each other out. If the TOTAL Impulse is zero there will be NO change in total momentum. So momentum must be conserved during the collision.

The situation with kinetic energy is different. Kinetic energy is changed by Work, defined as force times distance. While the two forces acting on the two objects are equal and opposite (as described above), the distances traveled by the two objects during the collision are NOT necessarily equal to each other. So kinetic energy is not automatically conserved.

One of the requirements of an inelastic collision is one in which the two objects colliding do NOT travel the same distance during the collision.

Answer from: Quest

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6 $\frac{m}{s^{2} }$

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s

Answer from: Quest

Hypothesis. why don’t you know this? i learned this stuff in like 5th grade

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