500 kg elevator is supported by a cable with a tension of 3000 N. Determine the magnitude and direction of the elevator’s acceleration.

nah.   i'm just sleepy.

v=ir = 3x15 =45 v

so easy. just google the electromagnetic waves and it’ll pop up.

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer