A tennis ball thrown with a velocity of 25m/s[Fwd] in the horizontal direction from the top of an 80m high building. 1. How long does it take the tennis ball to reach the ground?
2. How far is the range (how far from the base of the building will the ball land) ?
3. What is the final velocity?
Even answering one will help me out and i will give brainlest!

d hope you get it right

Explanation:

Explanation:

Ignoring air resistance

1) from vertical rest

s = ½at²

t = √(2s/a)

t = √(2(80)/9.8)

t = 4.040610...

t = 4.0 s

2) d = vt

   d = 25(4.0)

   d = 100 m

3) v² = u² + 2as

   v² = 25² + 2(9.8)(80)

   v² = 2193

   v = 46.8294...

    v = 47 m/s

θ = - 90 + arcsin(25/46.8294)

θ = -57.7339...

θ = 58° below the horizontal

when a device is used in a circuit in which the voltage is 81 v, the current flowing through the device is 3 a. what is the resistance of the device?

a. 27 ω

b. 40.5 a

c. 243 ω

d. 243 a

the correct answer is a. 27