A heat-engine cycle is executed with steam in the saturation dome between the pressure limits of 7 MPa and 2 MPa. If heat is supplied to the heat engine at a rate of 150 kJ/s, the maximum power output of this heat engine is . Solve using appropriate software. Multiple Choice

19.72kW

Explanation:

At P1 = 7 MPa, the saturated temperature T1 = 285.83°C. This will be converted to Kelvin

= 285.83 + 273

= 558.83K

At P2 = 2 MPa, the saturated temperature T1 = 212.38°C. This will be converted to Kelvin

= 212.38 + 273

= 485.38K

Then, the maximum possible efficiency which is the Carnot efficiency will be:

= 1 - T2/T1

= 1 - 485.38/558.83

= 1 - 0.8686

= 0.1314

Then, the the maximum power output of this heat engine will be:

= 0.1314 × 150 kJ/s

= 19.72kW

a solenoid is created by wrapping a l = 90 m long wire around a hollow tube of diameter d = 4.5 cm.   the wire diameter is d = 0.9 mm.   the solenoid wire is then connected to a power supply so that a current of i = 9 a flows through the wire.

randomized variablesl = 90 m

d = 4.5 cm

d = 0.9 mm

i = 9 a                                          

write an expression for the number of turns, n, in the solenoid. you do not need to take into account the diameter of the wire in this calculation.

calculate the number of turns, n, in the solenoid.

write an expression for the length of the solenoid (l2) in terms of the diameter of the hollow tube d.

calculate the length of the solenoid (l2)   in meters.

calculate the magnitude of the magnetic field at the center of the solenoid in teslas.

explanation: