If the length of the rod is 2.65 m, and the mass of the bob and the rod are both 1.4 kg, what is the period of this pendulum

  T = 5.66 s

Explanation:

The system formed by the bar plus ball forms a physical pendulum

        w =

the moment of inertia of a rod held at one end is

       I = m L²

we substitute

       w =

in this case the turning distance and the length of the rod are equal

        d = L

        w =

angular velocity and period are related

       w = 2π / T

        2π / T =

        T = 2π

let's calculate

       T = 2π

       T = 5.66 s

in simple terms, the principle states that the buoyancy force on an object is equal to the weight of the fluid displaced by the object, or the density of the fluid multiplied by the submerged volume times the gravitational acceleration, g. this is also known as upthrust.