Calculate the volume in milliliters of a 0.92m nickel(ii) chloride solution that contains 175. mmol of nickel(ii) chloride nici2). round your answer to 2 significant digits.

The volume of the solution is 190 milliliters.

Explanation:

Where :

n = moles of compound

V = Volume of solution in L

M = Molarity of solution

Moles of nickel(II) chloride = n  = 175 milli mol = 0.175 mol

1 milli mol = 0.001 mol

Volume of nickel(II) chloride solution = V

Molarity of the nickel(II) chloride = 0.92 M

1 L = 1000 mL

V = 0.1902 L= 0.1902 × 1000 mL =  190.2 mL ≈ 190 mL

The volume of the solution is 190 milliliters.

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml

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