2. A charge particle is moved through a potential difference of 154.5 V and experiences a
change of electric potential energy of 4.26 x 10-8 J. What is the charge of the particle?

2.76×10⁻¹⁰ C

Explanation:

Applying,

V = W/q Equation 1

Where V = Electric Potential, E = Electric potential energy, q = charge.

make q the subject of the equation

q = W/V Equation 2

From the question,

Given: W = 4.26×10⁻⁸ J, V = 154.5 V

Substitute these values into equation 2

q = 4.26×10⁻⁸/154.5

q = 2.76×10⁻¹⁰ C

f=ma newton's second law 7x8=56n

the small 0.38-kg slider is known to move from position a to position b along the vertical-plane slot. determine (a) the work done on the body by its weight and (b) the work done on the body by the spring. the distance r = 0.70 m, the spring modulus k = 154 n/m, and the unstretched length of the spring is 0.53 m

explanation:

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