A pair of oppositely charged plates is separated by 0.09 m. A potential difference of 285 V exists between the plates. What is the electric field that exists between the plates?

25.65 V/m

Explanation:

Applying,

V = Er Equation 1

Where V = Electric potential, E = electric field, r = distance of seperation.

make E the subject of the equation

E = V/r Equation 2

From the question,

Given: V = 285 V, r = 0.09 m

Substitute these values into equation 2

E = (285×0.09)

E = 25.65 V/m

Hence the electric field between the plates is 25.65 V/m

i would like to make dinner for my mom, dad, and sister

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards