1.Calculate the decrease in temperature when 4.00 L at 20.0 °C is compressed to 2.00 L.

Explanation:

First, Convert the temperature to Kelvin using K = oC + 273

K = 20.0oC + 273

K = 293 K.

Plug in the initial volume, initial temperature, and final volume in the equation V1xT1=V2xT2

4.00 X 293 = 2.00 X T2

Solve for T2:

4.00 X 293 = 2.00 X T2

1172= 2.00T2

1172 ÷ 2.00 = 2.00T2÷ 2.00

586 = T2

The previous answer tells you what it will decrease to, so the total decrease will be the initial temperature - the final temperature:

1172 - 586 = 586

The temperature decreases by 586K

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer