A point charge Q moves on the x-axis in the positive direction with a speed of 370 m/s. A point P is on the y-axis at y = + 80 mm. The magnetic field produced at point P, as the charge moves through the origin, is equal to - 0.8 μT k^. When the charge is at x = + 40 mm, what is the magnitude of the magnetic field at point P? (μ0 = 4π × 10-7 T • m/A) A. 0.57 μT
B. 1.1 μT
C. 0.92 μT
D. 0.74 μT

The answer is C:

Explanation:

HOPE IT HELPS!!

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14

causes

fossil fuels burn

cities become more industrialized

human population grows worldwide