A steel tape with a crosssectional area of 0.040 cm2and weight of 1.0 kg has a length of 31.010 m between the zero and the 30 m marks, when supported throughout at 200C and subject to a tension of 5 kg. This tape is used to measure a distance along a slope of 5degrees from horizontal and is supported throughout during the measurement. The tension applied is 16kg. The temperature of the tape is 150C. The measured slope distance is recorded as 400m. What is the corrected horizontal distance

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Let l be the vertical distance of pendulum when it makes 25.0 degree angle to verticalcos(25.0) = l / 1.20 ml = (1.20m)(cos 25.0)so the height, h, of the pendulum above the equilibrium position is h = 1.20m - (1.20m)(cos 25.0)ep,i + ek, i = ep, f = ek, fwhen pendulum held at 25.0 degrees, initial kinetic energy is 0 jwhen pendulum passes through equilibrium point, final potential energy is 0jep, i = ek fmgh = 1/2 m v^2gh = 1/2 m v^2v = √(2gh)v = √[2 * 9.81 m/s² * ( 1.20m - (1.20m)(cos 25.0) )]v = 1.5 m/s