A 0.150 kg cube of ice (frozen water) is floating in glycerin. The glycerin is in a tall cylinder that has inside radius 5.50 cm. The level of the glycerin is well below the top of the cylinder. Part A If the ice completely melts, by what distance does the height of liquid in the cylinder change

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A 0.150 kg cube fo ice (frozen water) is floating in glycerine. The glycerine is in a tall cylinder that has inside radius 3.10 cm. The level of the glycerine is well below the top of the cylinder.

Part A

If the ice completely melts, by what distance does the height of liquid in the cylinder change? Express your answer with the appropriate units.

Part B

Does the level of liquid rise or fall? That is, is the surface of the water above or below the original level of the glycerine before the ice melted?

Part A: 327 mm

              Part B: Rise

Explanation: When an object is submerged on a fluid, the fluid exerts a upward force on the object called Buoyant Force. It can be calculated by the following relation:

Part A

Because the ice cube is floating on glycerin, its forces are on equilibrium, which means buoyant and weight are equal:

Density of glycerine is 1260 kg/m³.

Volume of a cylinder is

Solving

m

After melted, the volume of a mass of water created is

Density of water is 10³ kg/m³.

1.58 m

The change in heights is

0.327 m

The distance by which the height of liquid in the cylinder change is 327mm.

Part B:

Water has more density than ice. So, when melted, water will take the place of glycerin more than ice and so, liquid will rise on the cylinder.