Hernando builds a simple DC series circuit with a standard D-cell battery and uses an ammeter to determine that the total current in the system is 3.0 A. In an attempt to increase the brightness of the bulbs in the circuit, he tries to increase the voltage by adding two more batteries (in series with the first). Calculate the new current when driven by three batteries.

Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge,    then the following gives us the potential difference,      the formula  may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get    using q = 8.00  × 10⁻¹⁹ c and  δv = 2.00 v, we get    the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.