A block mass m = 34 kg and a speed of v is behind a block mass M = 81 kg and a speed of .5m/s, as shown. The surface is frictionless and the blocks collide and a couple. After the collision, the blocks have a common speed of .9 m/s. What is the magnitude of the impulse on 34 kg block due to collisions? A. 32Ns
B. 14Ns
C. 41Ns
D. 52Ns
E. 73Ns

magnityde and direction

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards